Find the value of sin 45o - cos 30o - JAMB Mathematics 2009 Question

sin 45^o - cos 30^o

(\frac{1}{\sqrt{2}}) - (\frac{\sqrt{3}}{2})

= (\frac{2 - \sqrt{2} \times \sqrt{3}}{2\sqrt{2}}))

= (\frac{2 - \sqrt{6} \times \sqrt{2}}{2\sqrt{2} \sqrt{2}})

= (\frac{2\sqrt{2} - \sqrt{12}}{4})

= (\frac{2\sqrt{2} - 2\sqrt{3}}{4})

= (\frac{2(\sqrt{2} - \sqrt{3})}{4})

= (\frac{\sqrt{2} - \sqrt{3}}{2})